C数组指针函数指针做函数参数和返回值数组和函数不能用做参数和返回值，但数组指针和函数指针可以1数组指针做函数参数数组指针做函数参数，数组名用做实参时，其形参为指向数组首元素的指针（指针目标类型为数组元素）#include<stdi。
c语言指针接收数组的值?数组和函数不能用做参数和返回值，但数组指针和函数指针可以，我来为大家科普一下关于c语言指针接收数组的值?下面希望有你要的答案，我们一起来看看吧!
c语言指针接收数组的值
数组和函数不能用做参数和返回值，但数组指针和函数指针可以。
1 数组指针做函数参数
数组指针做函数参数，数组名用做实参时，其形参为指向数组首元素的指针（指针目标类型为数组元素）。
#include <stdio.h>#include <stdlib.h>#define ROWS 3#define COLS 2void fun1(int (*)[COLS], int);int main(){int array_2D[ROWS][COLS] = { {1, 2}, {3, 4}, {5, 6} };int rows = ROWS;/* works here because array_2d is still in scope and still an array */printf("MAIN: %zu\n",sizeof(array_2D)/sizeof(array_2D[0]));fun1(array_2D, rows);getchar();return EXIT_SUCCESS;}void fun1(int (*a)[COLS], int rows){int i, j;int n, m;n = rows;/* Works, because that information is passed (as "COLS").It is also redundant because that value is known at compile time (in "COLS"). */m = (int) (sizeof(a[0])/sizeof(a[0][0]));/* Does not work here because the "decay" in "pointer decay" is meantliterally--information is lost. */printf("FUN1: %zu\n",sizeof(a)/sizeof(a[0]));for (i = 0; i < n; i) {for (j = 0; j < m; j) {printf("array[%d][%d]=%d\n", i, j, a[i][j]);}}}
2 数组指针做函数返回值
数组指针做函数返回值时，数组指针是指指针目标类型为数组元素的指针。
#include <stdio.h>#include <malloc.h>char(*weekday())[5]{char(*wee)[5] = (char(*)[5])malloc(sizeof(char)*5*7);char* str[] = {"Mon.","Tue","Wed.","Thu.","Fri.","Sat.","Sun."};for(int i=0;i<7;i)for(int j=0;j<5;j)wee[i][j] = str[i][j];return wee;}int main(){char(*week)[5] = weekday();for(int i=0;i<7;i)printf("%s\n",week[i]);free(week);setbuf(stdin,NULL);getchar();}
3 函数指针做函数参数
函数指针做函数参数，可以封装函数体中因因应不同需求而需“变化”的代码，避免“硬”编程，让代码更加通用和泛化。
#include <stdio.h>void sort(int arr[],int size,bool(*comp)(int,int)){for(int i=0;i<size-1;i)for(int j=0;j<size-i-1;j)if(comp(arr[j],arr[j 1])){int t = arr[j 1];arr[j 1] = arr[j];arr[j]=t;}}bool Comp(int a,int b){return a<b;}int main(void){int arr[]={2,1,4,5,3,9,6,8,7};int n = sizeof arr / sizeof *arr;sort(arr,n,Comp);for(int i=0;i<n;i)printf("%d ",arr[i]);getchar();return 0;}
4 函数指针做函数返回值
用函数返回函数指针，可以让同类函数具有相同的接口。
#include <stdio.h>enum Op{ADD = ' ',SUB = '-',};int add(int a, int b){return ab;}int sub(int a, int b){return a - b;}/* getmath: return the appropriate math function */int (*getmath(enum Op op))(int,int){switch (op){case ADD:return &add;case SUB:return ⊂default:return NULL;}}int main(void){int a, b, c;int (*fp)(int,int);fp = getmath(ADD);a = 1, b = 2;c = (*fp)(a, b);printf("%d%d = %d\n", a, b, c);getchar();return 0;}
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